$(X+4)=X^4+X^3+X^2+X+1 \pmod{5}$ by ramification of prime ideals

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In Milne's algebraic number theory notes, on page 65, there is the following example:

$X^4+X^3+X^2+X+1\equiv(X+4)^4\pmod{5}$.

And Milne asks: Why is that obvious?
This comes after discussion of ramification of prime ideals in number fields.

My attempt so far:

Let $\omega_5=e^{2\pi i/5}$. The field extension $\mathbb{Q}\subset\mathbb{Q}(\omega_5)=K$ is Galois and of degree $4$. The minimal polynomial of $\omega_5$ over $\mathbb{Q}$ is $f(X)=X^4+X^3+X^2+X+1$.
Consider prime ideal $(5)\lhd\mathbb{Z}$ and its factorization in the ring of integers $\mathcal{O}_K$.

I'm not sure how to proceed.