If $X,Y$ are second countable Baire spaces, so is $X\times Y$. ?
If true, a suggestion to try thanks
If $X,Y$ are second countable Baire spaces, so is $X\times Y$. ?
If true, a suggestion to try thanks
On
HINT: Let $\mathscr{B}$ be a countable base for $Y$. Let $\pi_X:X\times Y\to X$ be the usual projection map. Suppose that $G_n$ is a dense open subset of $X\times Y$ for each $n\in\Bbb N$.
Let $D_n=\bigcap_{B\in\mathscr{B}}\pi_X[G_n\cap(X\times B)]$.
Let $D=\bigcap_{n\in\Bbb N}D_n$.
(Note that I did not need to assume that $X$ was second countable.)
Yes. It suffices $X$ to be second countable for $X\times Y$ be Baire, by Theorem 5.1.viii from [HC].
[HC] R. C. Haworth, R. C. McCoy, Baire spaces, Warszawa, Panstwowe Wydawnictwo Naukowe, 1977.