I have been stuck to this question lately
$(5 + \sqrt{24})^x + (5 - \sqrt{24})^x = 10$ , solve for $x$
HINT:
$$(5+\sqrt{24})(5-\sqrt{24})=1$$
Let $(5+\sqrt{24})^x=y\iff(5-\sqrt{24})^x=\dfrac1{(5+\sqrt{24})^x}=?$
Now solve for $y$
Now if $\displaystyle u^m=u^n,$
either $\displaystyle m-n=0,u\ne0; $
or $\displaystyle u=1$
or $\displaystyle u=-1,m-n$ is even
HINT
Well, the answer is $x= \pm 1$.
Realize that the function on the left is increasing for $x \ge 0$ and decreasing for $x \le 0$.
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HINT:
$$(5+\sqrt{24})(5-\sqrt{24})=1$$
Let $(5+\sqrt{24})^x=y\iff(5-\sqrt{24})^x=\dfrac1{(5+\sqrt{24})^x}=?$
Now solve for $y$
Now if $\displaystyle u^m=u^n,$
either $\displaystyle m-n=0,u\ne0; $
or $\displaystyle u=1$
or $\displaystyle u=-1,m-n$ is even