A cat chases a rat. For every $5$ leaps of the rat , the cat takes $3$ leaps

Question

problem A cat chases a rat. For every $5$ leaps of the rat , the cat takes $3$ leaps, but the $2$ leaps of the cat are the same as $3$ leaps of the rat. Compare the speeds of the cat and the rat

a)$4:5$

b)$12:13$

c)$16:15$

d)none of these

solution

clearly the $2$ leaps of the cat are the same as $3$ leaps of the rat

so let distance of rat leap be $x$

then distance of cat's leap =$ \frac {3x}{2} $

then speed ratio = $ \frac {4.5x}{5x} $

$ \frac {9}{10} $

Am I right $?$

Answer 1

I see no fault in your answer.

Answer 2

Quicker an simple Assume 2 leaps of cat = 3 leaps of rat=6meter(lcm of 2;3) NowNow 3 leap of cat is 9 m Rat 5 leap is 10 meter Ratio = distance /time Time is same So ratio 9/10