A dice is thrown six times, Find the probablity of getting the six numbers in any order.

Question

For example, getting all the posible numbers (from 1 to 6) in ascendant or descendant order is $\dfrac{2}{6^{6}}$, because the only pisibilities are (1,2,3,4,5,6) and (6,5,4,3,2,1).

But, i don't understand what is the difference when you want to get the six numbers in any order and also, the probability of only getting odd numbers.

Thanks.

Answer 1

HINT

The possile arrangements for the six numbers are simply the permutations that is $6!$