A fly has a lifespan of $4$–$6$ days. What is the probability that the fly will die at exactly $5$ days?
A) $\frac{1}{2}$
B) $\frac{1}{4}$
C) $\frac{1}{3}$
D) $0$
The solution given is "Here since the probabilities are continuous, the probabilities form a mass function. The probability of a certain event is calculated by finding the area under the curve for the given conditions. Here since we’re trying to calculate the probability of the fly dying at exactly 5 days – the area under the curve would be 0. Also to come to think of it, the probability if dying at exactly 5 days is impossible for us to even figure out since we cannot measure with infinite precision if it was exactly 5 days."
But I do not seem to understand the solution, can anyone help here ?
Since as you say the probability is the area under the curve of the PDF, then $$P(a \leq X \leq b) = \int\limits_a^b f_X(x) \ dx$$ where $f_X(x)$ is the PDF of $X$, which is the random variable describing the probability that the fly will die at time $X = x$. Now since you are interested in $P(X = a)$, then $$P(X = x) = P(a \leq X \leq a) = \int\limits_a^a f_X(x) \ dx = 0$$