I want an argument for why this is true, implying that such lambda are in the resolvent set.
I have tried to construct pathological examples in order to understand this fact, but I still don't get it.
I suspect the solution is embarrassingly simple.
I want an argument for why this is true, implying that such lambda are in the resolvent set.
I have tried to construct pathological examples in order to understand this fact, but I still don't get it.
I suspect the solution is embarrassingly simple.
If $A$ is self-adjoint, then then the spectrum of $A$ is contained in $ \mathbb R$. You can find this result in nearly every book on operator theory.