Let $T$ be a closed unbounded operator with compact resolvent, this means that there exists $\lambda_0 \in \rho(T)$ such that $(T- \lambda_0)^{-1}$ is compact.
Is it true that $\forall \lambda \in \rho(T)$we have $(T- \lambda)^{-1}$ is compact??
2026-02-22 21:15:30.1771794930
Operator with compact resolvent
637 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in SPECTRAL-THEORY
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