A limit using the Euler number: $\lim_{n\rightarrow\infty}\frac{n!}{(n-i)!}\left(\frac{c}{n}\right)^{n-i}$

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What is answer of this limit and how can I get it? $c$ and $i$ are constants. $$\lim_{n\rightarrow\infty}\frac{n!}{(n-i)!}\left(\frac{c}{n}\right)^{n-i}$$ I guess it will envolve some Neper/the Euler number $e$. I tried to rearrange terms of factorial and exponents in a good way but I couldn't make any conclusion so I think couldn't find the nice shape of writing this expression.

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Hint. We assume $c,i$ are any fixed real numbers.

By setting $\displaystyle u_n=\frac{n!}{(n-i)!}\left(\frac{c}{n}\right)^{n-i}$, one gets, as $n \to \infty$, $$ \begin{align} \frac{u_{n+1}}{u_n}&=\frac{(n+1)!}{(n+1-i)!}\left(\frac{c}{n+1}\right)^{n+1-i}\cdot \frac{(n-i)!}{n!}\left(\frac{n}{c}\right)^{n-i} \\\\&=\frac{(n+1)}{(n+1-i)}\cdot \frac{c}{n+1}\cdot \left(1+\frac1n \right)^{-n+i} \\\\& \sim \frac{c}{e(n+1)} \\\\& \to 0. \end{align} $$ Can you take it from here?