A model of fox and rabbit population with baseline conditions

266 Views Asked by At

The population of foxes and rabbits on Nantucket Island has been studied by biologists. They measure the populations relative to a baseline, in hundreds of animals. (So $x(2)=5$ means that there are 500 more foxes than the baseline value, and $y(2)=−5$ means that there are 500 fewer rabbits than the baseline value.)

The biologists have established the following relationship between $x(t)$ (foxes' population) and $y(t)$ (rabbits' population): \begin{align} x' &= 0.5x + y \\ y' &= -2.25x + 0.5y \end{align}

Suppose that at $t=0$ there are $100$ more foxes than the baseline: $x(0) = 1$; the rabbit population is at the baseline value, $y(0) = 0$. What is the solution to this initial value problem?

From solving the characteristic equations, I got that $\lambda = 0.5 \pm 1.5i$. Since using either value yields the same answer, let $\lambda = 0.5 - 1.5i$. Then from solving the system for the eigenvector, I get that the eigenvector is $\binom{i}{1.5}$. Hence the complex solution is $\binom{i}{1.5}e^{(0.5 - 1.5i)t}$.

Using the Euler's formula $e^{iwt} = \cos(\omega t) + i\sin(\omega t)$, I get the real parts of $x$ and $y$ is given by

$$\binom{x}{y} = e^{0.5t} \binom{0}{1.5} \cos(1.5t) + e^{0.5t}\binom{1}{0} \sin(1.5t).$$

And given that $x(0) = 1$ and $y(0) = 0$, I arrived at: \begin{align} x(t) &= \sin(1.5t) e^{0.5t} + e^{0.5t} \\ y(t) &= 1.5\cos(1.5t) e^{0.5t} - 1.5e^{0.5t} \end{align}

However, these equations turned out to be the wrong model.