A nabla operator identity in ortho-normal coordinate systems

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Let $u_1,~u_2,~u_3$ be components of the position vector $\vec{u}$:

$$\vec{u}=u_1 \vec{e}_{u_1}+u_2 \vec{e}_{u_2}+u_3 \vec{e}_{u_3}$$

in an ortho-normal coordinate system (not necessarily Cartesian) spun by the ortho-normal basis $\{\vec{e}_{u_1},\vec{e}_{u_2},\vec{e}_{u_3}\}$.

Prove:

$$\nabla\cdot\left(\nabla u_1\times\nabla u_2\right)=0$$

I am mostly interested in the general non-Cartesian case.