A needle in a haystack problem: how do my chances compare to a lottery?

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Please forgive me if this is too outrageously vague a question; it is only meant as idle speculation, really, but sometimes it is good to let one's mind wander a bit.

In the last year or so there has been a huge increase in advertising for gambling, and apart from the ethical and psychological aspects of gambling, I thought about what one can compare one's chances of actually winning in, eg. a lottery. So, my question is, how does it compare to finding a needle in a haystack? The relevance of this question is that when people buy a lottery ticket, they don't really understand how unlikely winning is, but most have an intuition about the chances of finding the nail in a haystack.

So, if we consider a realistic size of haystack containing one needle, and I were to put my hand somewhere in the haystack and pull out whatever I grabbed hold of, what are the chances that it might be the needle - and how does it compare to winning in the lottery?

I haven't touched combinatorics or probability theory since I left university some 35 years ago, so I have very little skill in this area, but I realise it may be unanswerable, so perhaps this question is as much about the method - starting with deciding which lottery (eg. the EuroLotto, or whatever it is called) and which haystack, as well as deciding how much freedom one has in placing the hand.

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Just as a toy example, the chance of a winning ticket for the UK National Lottery is around one in $45$ million. Let's find out how big a cubic haystack would have to be for me to have the same odds of finding a needle in it.

Say I can grab a handful of radius $r$ and the haystack is a cube of side $s$. Then $$s^3 = 4.5\times 10^7\times\frac{4\pi}{3}r^3$$

Taking the cube root of both sides, $$s \approx 573r$$

Even taking a fairly small $r$, say $r\approx 5\text{cm}$, this means a haystack of side around $28\text{m}$, which is very big.


Obviously these calculations involve approximations and assumptions, but hopefully the above shows how you could get a rough idea (which I think is appropriate here; the haystack is considerably larger than a real one, but isn't, say, the size of the moon).