How do you solve for $x$ in $\frac{N^x}{1.2x(0.25-x)}>\log N$?
It does not seen to succumb to standard techniques.
Is there a good bound on $x$?
How do you solve for $x$ in $\frac{N^x}{1.2x(0.25-x)}>\log N$?
It does not seen to succumb to standard techniques.
Is there a good bound on $x$?
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