Is $x=i²$ the solution of this equation $2018^x+2018x+2018=0 $ in $\mathbb{C}$?

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Wolfram alpha showed that the solution of that equation $2018^x+2018x+2018=0 $ closed to $x=-1$ , Then can I consider that $x=i^2$ is the solution of the titled equation in $\mathbb{C}$ ?