About the definition of an oscillatory differential equation and Hill's equation

90 Views Asked by At

My questions comes from reading the book The Spectral Theory of Periodic Differential Equations by Eastham.

Consider the following differential equation:

$[p(x)y'(x)]' + [\lambda s(x) + q(x)]y(x) = 0$

where $\lambda \in \mathbb{R}$, $p(x), s(x), q(x)$ are real valued, piece-wise continuous, and with period $a$. Also we assume that $s(x) \geq s>0$ and that $p(x)$ is never zero.

Now we can consider the periodic problem with the initial condtions that $y(a) = y(0), y'(a) = y'(0)$.

This problem is self adjoint, and the book states that there are an infinite countable eigenvalues, which can be ordered as such:

$\lambda_0 \leq \lambda_1 \leq \lambda_2...$

enter image description here

Question 1:

Is this a complete characterization of the eigenvalues? That is, will every value of $\lambda$ for which there is a solution to the above equation with the above initial conditions be counted within that countable set?

Further down the book, he gives this definition:

The above differential equation is called oscillatory if it has a non-trivial solution with an infinite number of roots in $\mathbb{R}$.

Then this theorem follows:

If $\lambda > \lambda_0$ (from above), then the above equation is oscillatory.

enter image description here

Question 2:

How do I know that for every $\lambda$ there is a non-trivial solution to the equation? Can that equation be solved for any real valued $\lambda$ without specifying initial conditions?