Addition inside root problem

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Help me calculate the answer for$$ \sqrt{3+\sqrt 5}\cdot \sqrt{3-\sqrt 5}$$ (NO CALCULATOR ALLOWED). The answer in the book is "2" but I don't know how they solved it.

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Remember these rules:

  • $\sqrt A\times \sqrt B=\sqrt {AB}, ~ A,B≥0$

  • $(A-B)(A+B)=A^2-B^2$

Then you can start:

$$\sqrt {A+\sqrt B}× \sqrt {A-\sqrt B}=\sqrt {(A+\sqrt B)×(A-\sqrt B)}=...$$