there will be an $a$ let's prove $-a$ is unique.
let's assume there are 2 additive inverses $b$ and $c$ therefore $a+b=a+c$
let's multiply them by the multiplicative inverse of $a$
I try to use the multiplicative inverse but it does not work.
there will be an $a$ let's prove $-a$ is unique.
let's assume there are 2 additive inverses $b$ and $c$ therefore $a+b=a+c$
let's multiply them by the multiplicative inverse of $a$
I try to use the multiplicative inverse but it does not work.
Let $b$ and $c$ be two additive inverses for $a$. Then:
$$b=b+0=b+(a+c)=(b+a)+c=0+c=c$$