Consider the equation,
$$\frac{1}{y}-\frac{1}{x}=c$$
here $c$ is any constant.
So letting $c=0$, we get
$$\frac{1}{y}-\frac{1}{x}=0 \implies \frac{1}{y}=\frac{1}{x}$$
Now this is a straight line but I'm not sure whether origin lies on this line that is does this line passes through origin or not since $x,y$ are in denominator? Does that change anything from the equation of line $y=x$?
2026-05-15 16:00:35.1778860835
Ambiguity in a graph
30 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
1
Your original equation can't be evaluated when $x=0$ or $y=0$ because it contains undefined expressions, so no such values are solutions. It would be wrong to say that $\frac10-\frac10=0$.
However, a natural "fix" is to multiply through by $xy$, yielding $x-y=cxy$. This equation has the same solutions as the original one in the original domain, plus potentially new solutions on the coordinate axes. Indeed, when $c=0$,the origin $x=y=0$ satisfies the new equation.