An empty metal container (without its handle) weight 15% of its weight when filled with a particular liquid. After adding the handle, the weight of the fully filled container increases by 5%. If the weight of a partly filled container is 1/3 of the completely filled container with handle attached, then what fraction of container is utilized?
a) 4/17
b) 3/17
c) 6/19
d) 3/19
My equations are:
$e=0.15W$
$e+h+L=1.05 \cdot 0.15W$
$0.5L+e=1/3(e+L+h)$
$e$ is weight of empty container without handle,
$h$ is weight of the handle of the container,
$L$ is the weight of the liquid inside the container.
$W$ is weight of utilised container.
How can equation of four variables be solved by three equations?
Or are there any other approach?