We are given an rectangle ABCD. M and N are the middles of AC and BD. Prove that $$\overrightarrow{MN}=\frac{1}{2}(\overrightarrow{AB}+\overrightarrow{CD})=\frac{1}{2}(\overrightarrow{AD}+\overrightarrow{CB})$$
2026-03-28 02:41:10.1774665670
Anallytic geometry problem
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The hint.
All rectangle is a parallelogram.
Prove that $\vec{MN}=\vec{0}$, $\vec{AB}+\vec{CD}=\vec{0}$ and $\vec{AD}+\vec{CB}=\vec{0}$.