$\mathbb{Q}$ has the topology induced from $\mathbb{R}$, therefore it is in principle possible to talk about power series and define analytic functions on $\mathbb{Q}$ to be power series (with coefficients in $\mathbb{Q}$) that converge on some open subset of $\mathbb{Q}$ and only take values in $\mathbb{Q}$. I have a strong feeling that the only possible examples should be polynomials, but I cannot think of an easy proof. Any hints or counterexamples?
2026-03-26 03:11:00.1774494660
Analytic functions on $\mathbb{Q}$
51 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
2
I know of one counterexampe: $f(x) = 1 + x + x^2 + \ldots$ which on the appropriate open subset of $\mathbb{Q}$ equals $f(x) = \frac{1}{1-x}$, and hence sends rationals to rationals.
Still the modified question "Can the set of power series that are convergent on some open subset of $\mathbb{Q}$ and converge to rational numbers only on that set be characterized in a different, appealing way?" is very interesting I think.