Analytical solution to the equation $\sin(n \theta) / \sin(m \theta) = a$.

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I'm looking for an analytical solution to the equation $$\frac{\sin n\theta}{\sin m\theta}=a \quad (n,m\in\mathbb Z)$$ where the constant $a$ is real and can be both positive and negative.

The solution is needed for the unknown $\theta$; the rest of the parameters are known.

One approach I took was to write the sine functions as $\sim (e^{i x} - e^{-ix})$ which resulted in a polynomial equation of degrees set by $n$ and $m$, with no apparent analytical solution.

Is there an alternative route that can be taken, even by using special functions?

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You said you have attempted to convert your issue into a polynomial equation. But do you know that there already exists "on the shelf" Chebyshev polynomials of the second kind $U_n$ :

$$\displaystyle U_{n-1}(\cos \theta )=\frac {\sin n \,\theta}{\sin \theta }$$

giving

$$U_{n-1}(x)=a U_{m-1}(x)$$

which is a $\max(n,m)-1$ polynomial equation in $x:=\cos \theta$, keeping the roots whose absolute values are at most $1$.

Therefore, your question has essentially a negative answer: looking for an explicit analytical formula is elusive, because in general, above degree 4, most polynomial equations do not have "formulas" for their roots...

Remark 1: connection with hypergeometric function $ {}_{2}F_{1}$ (you find it in the Wikipedia article):

$$U_{n}(x)=(n+1)\ {}_{2}F_{1}\left(-n,n+2;{\tfrac {3}{2}};{\tfrac {1}{2}}(1-x)\right)$$

Remark 2: A completely different approach would be to write your equation under a form involving the cardinal sine function $\operatorname{sinc}$ i.e.,

$$ \frac{\operatorname{sinc}(n \theta)}{\operatorname{sinc}(m \theta)}=\frac{n}{m} a$$