Following problem is an exercise in "Complex variables with application - S. Ponnusamy"
Suppose that $f(z)$ is continuous, but not necessarily analytic, on an contour $C$. Show that the function $$F(z)=\int_{C}\frac{f(\zeta)}{\zeta-z}d\zeta$$ is analytic at each $z$ not on $C$, with $$F'(z)=\int_{C}\frac{f(\zeta)}{(\zeta-s)^{2}}d\zeta.$$
Is it possible to apply the Morera's theorem showing this problem?
It seems related, but there is no progress.
My attempt is as follows:
For any $z\not\in C$, choose $|h|>0$ small enough so that the line segment from $z$ to $z+h$ don't across $C$. Then, we have $$\Bigg|\frac{F(z+h)-F(z)}{h}-F'(z)\Bigg|\le|h|\cdot\int_{C}\frac{|f(\zeta)|}{|\zeta-z-h|\cdot|\zeta-z|^2}|d\zeta|.$$ Now, take $|h|\to0$, we see that $F$ is analytic at each $z$ not on $C$.
Give some advice. Thank you!