While it's certainly interesting that we can extend fields in surprising ways, are the "first example" type field extensions actually useful for anything? In particular, what about the field $$\Bbb Q[\sqrt{2}] = \{a+b\sqrt{2} \mid a,b \in \Bbb Q\}$$ Does this field help us describe anything or to solve any problems? What's the use of this field?
2025-01-13 02:37:01.1736735821
Applications for $\mathbb Q(\sqrt 2)$
778 Views Asked by user280243 https://math.techqa.club/user/user280243/detail At
1
There are 1 best solutions below
Related Questions in ABSTRACT-ALGEBRA
- Projective Indecomposable modules of quiver algebra
- Binary relations for Cobb-Douglas
- Relations among these polynomials
- Number of necklaces of 16 beads with 8 red beads, 4 green beads and 4 yellow beads
- Page 99 of Hindry's Arithmetics, follows from exact sequence that $\text{N}(IJ) = \text{N}(J)\text{card}(J/IJ)$?
- How to write the identity permutation as a product of transpositions
- Is $H$ a subgroup?
- $x=(0,\overline{1})$ and $y=(0,\overline{2})$ generate the same ideal in $R=\mathbb{Z}\times\mathbb{Z}/5\mathbb{Z}$
- Having some problems with understanding conics and graphing (eccentricity)
- Is this Cayley Diagram contradictory?
Related Questions in FIELD-THEORY
- Does there exist a maximal Archimedean ordered field?
- If $f,g$ are non-zero polynomials and $f$ divides $g$, then $\partial f \leq \partial g$.
- Show that the quotient ring $R/\mathcal{I}$ is a field.
- Constructing finite fields of order $8$ and $27$ or any non-prime
- Prove there is a polynomial $P_0$ with the property that $\mathcal{I}$ consists precisely of the multiples of $P_0$.
- Example of an algebraic extension which is not a radical extension
- If the degree of $\alpha$ is prime, then it equals the degree of $\alpha^q$ for every other prime $q$?
- Is there concrete example of finite extension which is not normal?
- Does a field extension equal $F(\alpha) = a_0+a_1\alpha+a_2\alpha^2+a_3\alpha^3+\cdots$
- Give $3$ examples of a field extensions which are neither normal nor separable.
Related Questions in EXTENSION-FIELD
- Example of an algebraic extension which is not a radical extension
- Is there concrete example of finite extension which is not normal?
- Are there non-abelian totally real extensions?
- Does a field extension equal $F(\alpha) = a_0+a_1\alpha+a_2\alpha^2+a_3\alpha^3+\cdots$
- The trace of $F|K$ is non degenerate if and only if the trace of $E\otimes_{K}F|E$ is nondegenerate
- If $\{a_{1},\ldots,a_{n}\}$ is a $K$-basis of $F$, then $\{1\otimes a_{1},\ldots,1\otimes a_{n}\}$ is an $E$-basis of $E\otimes_{K} F$.
- Is $\mathbb{Q}(\sqrt{2+\sqrt{-5}})$ normal over $\mathbb{Q}$
- Comparing degrees of field extensions: compositum over field versus field over intersection.
- Let $E$ be an algebraic extension of $F$. If every polynomial in $F[x]$ splits in $E$, show that $E$ is algebraically closed.
- Correspondence between Polynomial Roots and Automorphism Group
Trending Questions
- Induction on the number of equations
- How to convince a math teacher of this simple and obvious fact?
- Refuting the Anti-Cantor Cranks
- Find $E[XY|Y+Z=1 ]$
- Determine the adjoint of $\tilde Q(x)$ for $\tilde Q(x)u:=(Qu)(x)$ where $Q:U→L^2(Ω,ℝ^d$ is a Hilbert-Schmidt operator and $U$ is a Hilbert space
- Why does this innovative method of subtraction from a third grader always work?
- What are the Implications of having VΩ as a model for a theory?
- How do we know that the number $1$ is not equal to the number $-1$?
- Defining a Galois Field based on primitive element versus polynomial?
- Is computer science a branch of mathematics?
- Can't find the relationship between two columns of numbers. Please Help
- Is there a bijection of $\mathbb{R}^n$ with itself such that the forward map is connected but the inverse is not?
- Identification of a quadrilateral as a trapezoid, rectangle, or square
- A community project: prove (or disprove) that $\sum_{n\geq 1}\frac{\sin(2^n)}{n}$ is convergent
- Alternative way of expressing a quantied statement with "Some"
Popular # Hahtags
real-analysis
calculus
linear-algebra
probability
abstract-algebra
integration
sequences-and-series
combinatorics
general-topology
matrices
functional-analysis
complex-analysis
geometry
group-theory
algebra-precalculus
probability-theory
ordinary-differential-equations
limits
analysis
number-theory
measure-theory
elementary-number-theory
statistics
multivariable-calculus
functions
derivatives
discrete-mathematics
differential-geometry
inequality
trigonometry
Popular Questions
- How many squares actually ARE in this picture? Is this a trick question with no right answer?
- What is the difference between independent and mutually exclusive events?
- Visually stunning math concepts which are easy to explain
- taylor series of $\ln(1+x)$?
- Determine if vectors are linearly independent
- What does it mean to have a determinant equal to zero?
- How to find mean and median from histogram
- Difference between "≈", "≃", and "≅"
- Easy way of memorizing values of sine, cosine, and tangent
- How to calculate the intersection of two planes?
- What does "∈" mean?
- If you roll a fair six sided die twice, what's the probability that you get the same number both times?
- Probability of getting exactly 2 heads in 3 coins tossed with order not important?
- Fourier transform for dummies
- Limit of $(1+ x/n)^n$ when $n$ tends to infinity
Let me expand on the comments in a slightly different direction. The field $\Bbb Q(\sqrt2\,)$ and its ring of algebraic integers $\Bbb Z[\sqrt2\,]$ are no more “useful” than any other quadratic field, except for giving the simplest example of a real such field. It’s a principal ideal domain and so has unique factorization, and it (like the other real quadratic fields) has the interesting property that there are more units than just $\{\pm1\}$. These are the integers of the field whose reciprocals also are integers. I’m sure you noticed in high-school algebra that the reciprocal of $\sqrt2+1$ is $\sqrt2-1$. And it’s an interesting fact that every unit of $\Bbb Z[\sqrt2\,]$ is $\pm(1+\sqrt2)^m$ for some $m$. So you may say that this ring is useful as the simplest number field with infinitely many units — though others may give the honor to $\Bbb Z[\frac{1+\sqrt5}2]$.
The fact that $\Bbb Z[\sqrt2\,]$ has unique factorization is seriously interesting. Lots of other real quadratic rings do, and it’s an open question that infinitely many such have this property. The first real quadratic field without unique factorization in its ring of integers is $\Bbb Q(\sqrt{10}\,)$, where $6$ has the double factorization $2\cdot3=-(2-\sqrt{10}\,)(2+\sqrt{10}\,)$, though it takes just a little work to see that none of these four factors is related to another by a unit multiple.
For me, the moral of the story is that the quadratic number fields and their respective rings of integers give lots of examples of phenomena occurring generally in algebraic number theory, but yet these fields are easy to compute in.