A musician is currently producing three different songs. Let $A_i$ denote the event that song $i$ is completed by the end of the week, where $i\in\{1,2,3\}$. It is known these three events are independent with probabilities $P(A_1) = 0.4$, $P(A_2) = 0.3$, $P(A_3) = 0.1$. What is the probability that at most one of the three songs is completed by the end of the week?
This is what I thought, but I got it wrong: $$P(A_1\cap A_2\cap A_3)=P(A_1)P(A_2)P(A_3)=0.012$$ The answer given was $0.456$ I don't know how else to do this problem.
*I understand how to do this now, I'm trying to figure out if it asks for exactly one. I thought it was what was P((A_1 n A_2'n A_3')U(A_1'n A_2n A_3')U(A_1'n A_2'n A_3)) But I think that works for "at most one" not "exactly one".
Since its at most one of the three songs :-
P(Answer)= Probability of song 1 alone being published + Probability of song 2 alone being published + Probability of song 3 alone being published
But i agree with the @ConMan the should be another event where no one publishes a song this is how you get your answer
I think the question should be only one(exactly one) of the three songs published