Approximation to $1.05^{1.02}$ with Taylor's Theorem $T_2f(a;(x,y))$ in the point $a = (1,1)$

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Let $f : (0, \infty)^2 \to \mathbb{R}$ with $f(x,y) := x^y$.

How can one find out an approximation to $1.05^{1.02}$ with Taylor's Theorem, i.e. $T_2f(a;(x,y))$ in the point $a = (1,1)$.

And how can one calculate, that the absolute error of the approximation above is smaller than $7 \cdot 10^{-5}$?

For the first question I thought about using the "Symmetry of second derivatives". Apparently we are allowed to use the following theorem:

Let $D \in \mathbb{R}^n$ be an open set and $f \in C^k (D;\mathbb{R})$.

Further, let $i_1,..,i_k \in \text{{1,...n}}$.

Then we get

$$\frac{\partial^k f}{\partial x_{ik} \cdot \cdot \cdot \partial x_{i1}}(x) = \frac{\partial^k f}{\partial x_{\sigma(ik)} \cdot \cdot \cdot \partial x_{\sigma (i1)}} (x) $$

for all $x \in D$ and every permutation $\sigma:$ {$i_1,...,i_k$} $\to$ {$i_1,...,i_k$}.

I don't know how to continue though..