Are jumps of $C^2$ cadlag functions finite variation? Why are the discontinuous parts of Ito formula of finite variation?

48 Views Asked by At

Below is an excerpt from the proof of Ito's formula in the following post :https://almostsuremath.com/2010/01/25/the-generalized-ito-formula/#scn_genito_eq3

We assume $f$ to be a real $C^2$ function from some open subset $U \subset \mathbb{R}^d$ and $X$ is a $d$-dimensional semimartingale.

The statement below states that the terms inside the sum $$\Delta f(X_t) - D_i f(X_{t-})\Delta X_t^i - \frac{1}{2}D_{ij}f(X_{t-})\Delta X_t^i \Delta X_t^j$$ are all finite variation processes.

Why is this the case? I am not familiar with any thoerem stating that jumps of cadlag functions are of bounded variation. I would greatly appreciate if anyone could clear this up for me.

enter image description here