Consider 2 circles with radius r. Question is to find the area of the rhombus formed by joining the intersections. The edges of rhombus are the centers of the 2 circles and the 2 intersecting points.
2026-03-31 11:02:40.1774954960
Area of rhombus formed at the intersection of 2 circles
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You have two equilateral triangles, since the angles are all 60º. You only have to compute the height of one of the triangles with Pythagoras theorem, and then apply $$ A=\frac{bh}{2} $$
Finally, multiply by 2.