Area of triangle. Are there two solutions?

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In a right angled triangle there are sides a, b, and c at 500, 538.52, and 200 units respectively. The angle opposite of c, the 200 unit side is 10.7 degrees.

So using the rule in which the area of the triangle is 1/2absinC, the area of the triangle should be...

0.5*500*528.52*sin10.7

but that gives a result of 24996, which is the wrong answer because if we simply find the area using (200*500)/2 we get 50000.

Please explain.

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Note that $$\arctan \frac{200}{500}=21.8°$$

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thus the area is given by

$$A\approx \frac12\cdot500\cdot 538.52\cdot\sin 21.8°$$