Same colored cells have equal areas.
There is a grid consisting of NxN squares and a circle of Diameter N.
How do I find areas of the circle in each cell of the grid for any N . AFAIK, calculating 1/4 grid is enough because of symmetry.
2026-05-04 17:03:39.1777914219
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areas of parts of the circle in a grid
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I will only work on the second given figure. The most difficult part is finding the area of the red region.
In the first supplied diagram above, $\angle POR = 60^0$, and A = [Orange region] = [sector OPR] – [⊿OSR].
By symmetry, B = A.
[Blue region] = $A \cup B$ = [sector OPQ] – [Green square]
[Red region] = $A \cap B = A + B - A \cup B$

Hint:
The real challenge is for incomplete cells, of course.
You need to solve the integral
$$\int_a^b(\sqrt{1-x^2}-c)dx,$$ where $a,b$ correspond to verticals on the grid or to the intersection of the circle and the horizontal $y=c$.
$$I=\frac12\left.(x\sqrt{1-x^2}+\arcsin x-2cx)\right|_a^b.$$