Asymptotic form of the associated Legendre polynomials $P^m_l (z)$ at z=1

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I want to find the asymptotic form of $P^m_l (z)$ at z=1.

The usual method is to simply plug the limit into the differential equation and then solve the reduced differential equation.

There's a $ \frac{m^2}{(1 - z^2)}$ term that diverges in this case though. Is it possible to find the form in some other way?