Baby Rudin theorem 11.42

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There are the definitions which we need for the proof of the theorem : enter image description here

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There is the theorem: If ${f_n}$ is a Cauchy sequence in $\mathscr L^2(\mu)$ , then there exists a function $f$ $\in$ $\mathscr L^2(\mu)$ such that ${f_n}$ converges to $f$ in $\mathscr L^2(\mu)$ .

This says, in other words, that $\mathscr L^2(\mu)$ is a complete metric space.

There is the proof:

since ${f_n}$ is a Cauchy sequence, we can find a sequence ${n_k}$, $k$ $=$ $1,2,3,...,$ such that

$||f_{nk}-f_{n{k+1}}||$ $\lt$ $\frac {1}{2^k}$. ($k$ $=$ $1,2,3,...,$).

Choose a function $g$ $\in$ $\mathscr L^2(\mu)$ . By the Schwarz inequality,

$\int_{X} |g(f_{nk}-f_{n{k+1}})| d\mu $ $\leq$ $\frac {||g||}{2^k}$ .

Hence

$\sum_{k=1}^\infty $ $\int_{X} |g(f_{nk}-f_{n{k+1}})| d\mu $ $\leq$ $||g||$.

I couldn't understand How do we get the first inequality by the Schwarz inequality, and thereby, I also couldn't understand how do we get the last inequality ( $\sum_{k=1}^\infty $ $\int_{X} |g(f_{nk}-f_{n{k+1}})| d\mu $ $\leq$ $||g||$.)

Any help would be appreciated.