Bessel function, integrals equality

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How could I prove

$$ \int_{0}^{1} \frac{\cos(xu)}{\sqrt{1 - u^2}} \, du = \int_{1}^{\infty} \frac{\sin(xu)}{\sqrt{u^2 - 1}} \, du \ $$

?

Do I need to use Cauchy's Residue Theorem or is it possible to prove without complex analysis?

P.S. Both should be equal to $\frac{\pi}{2} J_0(x)$, but I want to prove it.