Trying to find the value of n.
$$_{20} C_{n+2} = _{20} C_{ 2n-1} $$
or
$$\mathrm{C}^{20}_{n+2} = \mathrm{C}^{20}_{2n-1}$$
Trying to find the value of n.
$$_{20} C_{n+2} = _{20} C_{ 2n-1} $$
or
$$\mathrm{C}^{20}_{n+2} = \mathrm{C}^{20}_{2n-1}$$
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Hint: $_{20}C_{20} = _{20}C_{0}$.
Second hint: $_{20}C_{5} = _{20}C_{15}$.
Can you take it from here?