This is for the probability that in a group of n people at least two have the same birthday, n = 3.
Hi, So for those who are familiar with the birthday paradox could you check my work:).
P(E) = [Event]/[SampleSpace]
Sample space = 365^3
Event = (365*364*363
P(E) = 0.991796
1-P(E) = 8.204 x 10^-3
This is where i am a bit lost, i dont know how to prove they are equal, any help is appreciated :).
You should define what $E$ is.
Any way, P(at least 2 have a common birthday) = $1 - 0.991796 = 0.008204$
which in scientific notation, becomes $8.204\times 10^{-3}$