One of popular tourist attractions in Alaska is watching black bears catch salmon swimming upstream to spawn. Not all "black" bears are black, though- some are tan-colored. Suppose that 6 black bears and 3 tan-colored bears are working the rapids of a salmon stream. Over the course of an hour, 6 different bears are sighted. What is the probability that those 6 include at least twice as many black bears as tan-colored bears?
Attempt: I need to use the hypergeometric distribution. That is P(K chosen) = [r_C_k * w_C_(n-k)]/N_C_n. There are 6 black bears and 3 tan for a total of 9 bears. Thus, N = 9. Please can someone please help me? I don't understand this problem. Thank you.
This does not happen when the sample of 6 sighted bears includes $____$ black bears and $____$ tan-colored bears. There are $k=$ $____$ ways to compose such a sample of 6 bears from the 9 in the stream, and $\ell=$ $____$ ways to compose any sample of 6 bears from the 9 in the stream hence the desired probability is $1-(k/\ell)=$ $____$.