Boolean vectors of length $6$ formed by exactly three zero's and three one's

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The boolean vectors formed by exactly three zero's and three one's are

$\binom{6}{3}\binom{6}{3}=400$

Is it wrong?

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Yes, it is wrong. Once you choose which three of the $6$ positions are $0$, the other three must be $1$.

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Hint: After you have chosen $3$ spots for the 0's, is there really anything more left to choose?