Bound in Prime Numbers

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I am currently working on Theorem 1.3 below. But, I was confused why $T_2$ is less than the product of primes( referring to the inequality that is encircle). It was stated in the proof that if $p$ satisfies $3n<p \leq n$ and also if $p$ satisfies $\frac{3n}{2}<p \leq 2n $ , it's power is $0$. I think that $T_2$ is subdivide into intervals but I don't get why it is less than. In my own understanding, it is equal. But, I guess I was wrong. Can someone help me out? This is the reference (http://www.m-hikari.com/ijcms-password/ijcms-password13-16-2006/elbachraouiIJCMS13-16-2006.pdf) enter image description here