Wolfram alpha tells me that $$ z \mapsto e^{iz^{1/2}}$$ does not have any branch cuts in the complex plane. However, I am skeptic. If this is true, can someone explain why? [Here is the wolfram result]
2025-01-13 05:55:45.1736747745
Branch cut of $e^{iz^{1/2}}$
196 Views Asked by Michael Angelo https://math.techqa.club/user/michael-angelo/detail At![[Here is the wolfram result]](https://i.stack.imgur.com/kP5oG.jpg){kind=link}
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