Branch point at infinity?

Question

I have to find the branch points of $f(z)=\left( z(z+1)\right )^{1/3}$. It is clear that $0$ and $-1$ are branch points, but I am not sure about infinity. Making the substituition $x=\frac{1}{z}$ and examining $f(x)=\left(\frac{1}{x}\left(\frac{1}{x}+1\right)\right )^{1/3}$, I do not really see what happens as x tends to 0, it just seems like the whole thing blows up. (Maybe this just simply means that infinity is not a branch point?)