Build a chain of sets $(A_{k})_{k \in \mathbb{N}}$ ($A_{k} \subseteq A_{k+1} \forall k$), that
if $k$ is even, then $A_{k}$ is recursive set
if $k$ is not even, then $A_{k}$ is non-computable set
Any help greatly appreciated. Thanks
Build a chain of sets $(A_{k})_{k \in \mathbb{N}}$ ($A_{k} \subseteq A_{k+1} \forall k$), that
if $k$ is even, then $A_{k}$ is recursive set
if $k$ is not even, then $A_{k}$ is non-computable set
Any help greatly appreciated. Thanks
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Let $p_0,p_1,\ldots$ enumerate the primes. Let $S\subset\mathbb{N}$ be a fixed non-computable set.
Start with $A_0=\emptyset$.
Then given $A_k$ for even $k$, let $A_{k+1}=A_k\cup\{p_{k/2}^s:s\in S\}$ and $A_{k+2}=A_k\cup\{p_{k/2}^n:n\in\mathbb{N}\}$.