The function is:
$$ f(x) = \ln\left(\frac{1-x}{x+2}\right) $$
I managed to calculate my domain: <-2,1>. My intersection with x is $ln(\frac{1}{2}) $ and with y is $-\frac{1}{2}$. I don't know how to calculate asimptotes since there is ln. I should be using L'Hôpital's rule but i cannot manage to find the solution.
at first it must be $$\frac{1-x}{x+2}>0$$ and this gives $$-2<x<1$$ asymptotes are $$x=-2$$ and $$x=1$$ the intersection with the x-axes is not right, you must solve the equation $$1=\frac{1-x}{x+2}$$ for $x$