The contour for the complex integral is the rectangle with vertices at $\left ( R,0 \right ), \left ( R,1 \right ),\left ( -R,1 \right ), \left ( -R,0 \right )$ The closed contour integral is equal to two pi times the residue at $z=\frac{i}{2}$. I am having major trouble expanding this in its Laurent series. Maybe the integral gurus here can provide answers.
2026-03-31 10:37:29.1774953449
Calculate $\int_{-\infty}^{\infty}\frac{e^{2x}}{\cosh \left ( \pi x \right )}dx$ using contour integration
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