Calculate number of solutions in $N$ of diophantine inequality :
$x_{1}+x_{2}+x_{3}\leqslant 6$
such as:
$x_{1}>1$ $;x_{2}\leqslant2 ;2<x_{3}<5 $
Solve this using generating functions.
Can someone give me some tips for how to even start with this or give me solution to some example ? Thank you.
With the conditions imposed on $x_1$ and $x_2$, the only choice for $x_3$ is $x_3=3$
With $x_3=3$ , the only choices for $x_2$ and $x_1$ are$x_2=1$ and $x_1=2$
Thus the only solution is $$( x_1, x_2, x_3 ) = (2,1,3)$$