If I have random lag times from a=0.1 to b=0.3 and a time to live (TTL) of x=0.25, what would be the packet loss in per cent?
Ok so basically I have packets that arrive in Random [a,b] time, if that random value is greater than x the packet gets lost and doesn't arrive.
What is the probability of a packet to arrive?
On
Assume that the time delay has a uniform distribution, then the probability of packet loss is given by the probability of the time delay being larger than 0.25.
This can be easily computed as $$(0.25-0.1)* \frac{1}{0.3-0.1} = 0.15*5 = 0.75$$
i.e, probability of packet arrival is $75\%$, and the probability of packet loss is $25\%$
You are taking a uniform random number in the range $[0.1,0.3]$ and asking the chance that it is less than $0.25$. You win in $0.25-0.1=0.15$ of the range of $0.3-0.1=0.2$, so the chance is $\frac {0.15}{0.2}=0.75$