suppose that we have following data
X
X =
332 428 354 1437 526 247 427
293 559 388 1527 567 239 258
372 767 562 1948 927 235 433
406 563 341 1507 544 324 407
386 608 396 1501 558 319 363
438 843 689 2345 1148 243 341
534 660 367 1620 638 414 407
460 699 484 1856 762 400 416
385 789 621 2366 1149 304 282
655 776 423 1848 759 495 486
584 995 548 2056 893 518 319
515 1097 887 2630 1167 561 284
[m,n]=size(X)
m =
12
n =
7
i have calculated centered data from this matrix and also covariance matrix
mean_matrix=X-repmat(mean(X),size(X,1),1);
and finally covariance matrix
covariance=(mean_matrix'*mean_matrix)/(12-1);
dimensions of this covariance is
[m1,n1]=size(covariance)
m1 =
7
n1 =
7
after that i have calculate eigenvalue decomposition
>> [V,D]=eig(covariance);
>> [e,i]=sort(diag(D),'descend');
>> sorted=V(:,i);
>> sorted
sorted =
-0.0728 0.5758 0.4040 -0.1140 -0.1687 -0.6737 -0.0678
-0.3281 0.4093 -0.2917 -0.6077 0.4265 0.1828 0.2348
-0.3026 -0.1001 -0.3402 0.3965 0.5682 -0.4320 -0.3406
-0.7532 -0.1082 0.0681 0.2942 -0.2848 0.0011 0.4987
-0.4653 -0.2439 0.3809 -0.3299 -0.0645 0.2076 -0.6503
-0.0911 0.6316 -0.2254 0.4135 -0.2366 0.4390 -0.3498
0.0588 0.1444 0.6599 0.3068 0.5705 0.3005 0.1741
>> e
e =
1.0e+05 *
2.7483
0.2642
0.0625
0.0230
0.0209
0.0034
0.0007
now i want to know about projection: is it $V'*X$ or $X*V$? please help me to clarify this things
Your vectors $V$ are eigen vectors of $covariance=X^TX$. I think these are columns of your matrix, but you can easily verify it multiplying your covariance matrix $covariance$ by columns and to verify property $Ax=\lambda x$.