It's a rectangle with 2 half elipses joined on the left and right side.
The rectangle itself is 3.55 X 2.54
The width of the whole shape (rectangle with 2 elipses) is 4.195.
Take away the width of the rectangle from the overall width
4.195 - 2.54 = 1.656
1.655 is the width of the 2 elipses. (0.8725 each)
Because I have the width of the 2 elipses as 1.655 when put together and the height as 3.55 can I accurately calculate the the area of the full shape?
The ellipses are the real problem here, the square shouldn't be very hard to tackle.
We have 2 identical half ellipses, giving us one full ellipse. Here's the dimensions if the ellipse:
$1.655 \text{ by }3.55$
The area of the ellipse is then $\pi\times 0.8275\times1.75$
Adding the area of the square gives us $$\pi\times 1.75\times0.8275+3.55\times2.54=1.448125\pi+9.017\approx13.566$$