In the triangle below, given the point A, angle θ and length d of the two equal sides, how can the points B and C be calculated?
Edit:After brainstorming for quite some time, I ended up with a complicated system that looks like that
$(x_1-x)^2+(y_1-y)^2=d^2$
$(x_2-x)^2+(y_2-y)^2=d^2$
$(x_1-x_2)^2+(y_1-y_2)^2=BC^2$
where
$BC^2=2d^2(1-cos\theta)$ (from the law of cosines)
Three equations, four unknowns. Unsolvable!
Update : I found the closest thing to a solution here : Finding Cartesian coordinates of remaining vertices of triangle, given a vertex and angle from y-axis but I'm missing the angle θ (angle between the height h of the triangle and the y axis)