I'm self teaching myself from a popular textbook for fun, the solutions are vague.
Here's the problems.
Cost of materials:
1.) Lid = ($2r$) per square unit
2.) Sides & bottom = ($r$) per square unit
Find the dimensions that of the box that minimze the total cost.
(Deleted)
Additional info:
V=hxy y=V/xh (Cost)=C=3rxy + 2rxh + 2ryh ΔC/ΔX=2rh-2rV/x^2=0 x^2=V/h x=y
I just realized that I added the solution from a different problem. My mistake.
For dimension $l,b,h$,
$$V=lbh$$
$$C=(2lb+lb+2(bh+lh))*r$$
By Lagranges' method,
$$c=(2lb+lb+2(bh+lh))*r+k(V-lbh)$$ Take partial derivatives of $c$ w.r.t. $l,b,h$ and express in terms of $k$ and solve for $k$ by substituting in $V-lbh=0$ equation.