One usually introduces the Gamma function to define a derivative of the factorial. However couldn't one define a derivative over integers like $$ f'(n) = \frac{f(n+1) - f(n)}{1} ? $$ Such a discrete alternative to the usual derivative would then allow us to simply compute a derivative of the factorial like $$ (n!)' = (n+1)! - n! = (n+1)n!-n! = n\ n! $$ My question is now: Is this the correct way to define a derivative over integer numbers and is the result for the derivative of the factorial correct? And how would one then compute the discrete integral/sum for the factorial?
2026-03-27 21:59:29.1774648769
Calculus over integers for derivative/integral of factorial?
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It's perfectly reasonable. These are called forward-finite-difference operators. On the same page of the link, you'll find a section on calculus for finite difference operators.
On the other hand, you might be interested in the definition of the Gamma function, which generalizes the factorial to non-integers and has a derivative in the classical sense.